Re: [xsl] Problem for : increment a variable in a for-each?

[David Carlisle <davidc@xxxxxxxxx>]

  It is my problem. no matter what I use, I can't find
  the position inside node which I filter from original
  source since position() will tell you the position on
  the source.


position() never refers to the position of a node in the original source
tree, it always refers to a position in the current node list.

So for example if you select a node with select="." it alsways has
position()=1 no matter where it is in teh tree as select="." selects one
node so that node is always the first (and only) node in the current
node list.

David


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