Subject: Re: [xsl] how to set the pattern to get the node From: que Li <queincanada@xxxxxxxx> Date: Tue, 30 Nov 2004 13:39:11 -0500 (EST) |
I am so confused that why I can use <xsl:when test="Parent_ID=1 or not(preceding-sibling::List[List_ID = $self/Parent_ID] or following-sibling::List[List_ID = $self/Parent_ID])"> to get node which I wnat but when I use <xsl:template match="List[Parent_ID=1or not(preceding-sibling::List[List_ID=Parent_ID] or following-sibling::List[List_ID=Parent_ID])]"> It is not filter properly Thanks --- Geert Josten <Geert.Josten@xxxxxxxxxxx> wrote: > Hi Que Li, > > > How I can get the node which parent_ID =1 or > parent_ID > > is not 1 but No other sibling node List_ID equal > to > > current node parent_ID > > > > I try to use: > > <xsl:template match="List[Parent_ID=1 or > > not(../List[List_ID = current()/Parent_ID])] "> > > The value of current() changes during the evaluation > of a Path in an XPath expression. It is not > pointing to the List element for which the math > pattern is being tested. > > Besides, you might want to rule out the List element > under consideration from the test on the siblings.. > > You could try the following: > > <xsl:template match="List"> > <xsl:variable name="self" select="."/> <!-- > current() can be shortened to . --> > <xsl:choose> > <xsl:when test="Parent_ID = 1"> > <!-- found a valid case --> > </xsl:when> > <xsl:when > test="not(preceding-sibling::List[List_ID = > $self/@Parent_ID] > or > following-sibling::List[List_ID = > $self/@Parent_ID])"> > <!-- found second valid case --> > </xsl:when> > <!-- xsl:otherwise? --> > </xsl:choose> > </xsl:template> > > Cheers, > Geert > > ______________________________________________________________________ Post your free ad now! http://personals.yahoo.ca
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