Re: [xsl] Creating unique groups

[Mukul Gandhi <mukul_gandhi@xxxxxxxxx>]

Hi Dave,
  Please try this XSL. It uses the Muenchian
technique.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">

<xsl:key name="by-group-name" match="group"
use="@name" />
    
<xsl:template match="/root">
  <root>
    <xsl:for-each select="group[generate-id(.) =
generate-id(key('by-group-name', @name)[1])]">
      <group name="{@name}">
        <xsl:for-each select="key('by-group-name',
@name)">
          <xsl:copy-of select="*"/>
        </xsl:for-each>
      </group>
    </xsl:for-each>
  </root>  
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

--- Dave Roe <david_roe@xxxxxxx> wrote:

> I have this XML representing 2 groups (spread across
> 4 group elements):
> 
> <root>
> 
> 	<group name="group1">
> 		<entry name="entry1" />
> 		<entry name="entry2" />
> 	</group>
> 
> 	<group name="group1">
> 		<entry name="entry3" />
> 	</group>
> 
> 	<group name="group2">
> 		<entry name="entry4" />
> 		<entry name="entry5" />
> 	</group>
> 
> 	<group name="group2">
> 		<entry name="entry6" />
> 	</group>
> 
> </root>
> 
> What would be the best approach to turn it into the
> following output, 
> where the name of the group is used as the
> identifier of what should be 
> a unique group element?
> 
> <root>
> 
> 	<group name="group1">
> 		<entry name="entry1" />
> 		<entry name="entry2" />
> 		<entry name="entry3" />
> 	</group>
> 
> 	<group name="group2">
> 		<entry name="entry4" />
> 		<entry name="entry5" />
> 		<entry name="entry6" />
> 	</group>
> 
> </root>
> 
> Right now, I just need someone to point me in the
> right direction to 
> get me started.
> 
> Thanks,
> /dave



		
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