Re: [xsl] HOW XSLT WILL BE, WHEN XML2XML TRANSFORMATION

[Marian Olteanu <mou_softwin@xxxxxxxxx>]

--- Arul Kumar <arulxml@xxxxxxxxxxxx> wrote:

> Hallow everybody,
> 
> I am processing XML to XML transformation by using xslt, in the meantime 
> I would like to clarify with you regarding the below one:
> 
> Input XML:
> <para>
> Text before equation
>     <equation>Equation text</equation>
>         Text before/after equation
>     <equation>Equation text</equation>
> Text after equation
> </para>
> 
> 
> Output XML:
> <p>Text before equation</p>
> <eqn>Equation text</eqn>
> <p>Text before/after equation</p>
> <eqn>Equation text</eqn>
> <p>Text after equation</p>
> 
> Please advise, how can I able to get above Output XML by using xslt, and 
> how the XSLT will be?
> 
> Best regards
> Arul Kumar

I would say:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="para/text()">
	<p>
		<xsl:value-of select="."/>
	</p>
</xsl:template>

<xsl:template match="para/equation">
	<eqn>
		<xsl:apply-templates/>
	</eqn>
</xsl:template>
</xsl:stylesheet>
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<


-----------------------------------
Marian
http://www.utdallas.edu/~mgo031000/



		
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