Re: [xsl] <xsl:number> in XPath

[Marian Olteanu <mou_softwin@xxxxxxxxx>]

> I want both the /menus/menu, the (//menu)[$pos] and their ancestors and first
> children, but i can't do something like
> 
> <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" | (//menu)[$pos]/menu
>  | ancestor:menu[(//menu)[$pos]]/>
> 
> or is there something similar?

If I understood right your requirement, it's
<xsl:apply-templates select="/menus/menu | (//menu)[$pos] | (//menu)[$pos]/menu
 | //menu)[$pos]]/ancestor::menu" />



=====
Marian
http://www.utdallas.edu/~mgo031000/

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