Subject: Re: [xsl] <xsl:number> in XPath From: Marian Olteanu <mou_softwin@xxxxxxxxx> Date: Thu, 9 Dec 2004 12:08:41 -0800 (PST) |
> I want both the /menus/menu, the (//menu)[$pos] and their ancestors and first > children, but i can't do something like > > <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" | (//menu)[$pos]/menu > | ancestor:menu[(//menu)[$pos]]/> > > or is there something similar? Sorry, I slipped an error first time. <xsl:apply-templates select="/menus/menu | (//menu)[$pos] | (//menu)[$pos]/menu | (//menu)[$pos]/ancestor::menu" /> ===== Marian http://www.utdallas.edu/~mgo031000/ __________________________________ Do you Yahoo!? All your favorites on one personal page Try My Yahoo! http://my.yahoo.com
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