Subject: [xsl] xsl:sort not working within xsl:choose From: "Hardy Merrill" <HMerrill@xxxxxxxxxxxxxxxx> Date: Fri, 10 Dec 2004 08:54:32 -0500 |
MSXML4 I'm passing a script parameter into the xsl style sheet that tells me what the sort field should be: <xsl:param name="select_sort_field"/> and then, within my for-each loop, I have the code to decide what to sort by: <xsl:for-each select="codes/value[code_type = $code_type]"> <xsl:choose> <xsl:when test="$select_sort_field"> <xsl:sort select="*[name()=$select_sort_field]" /> </xsl:when> <xsl:otherwise> <xsl:sort select="code" /> </xsl:otherwise> </xsl:choose> <!-- <xsl:sort select="code" /> --> <!-- <xsl:sort select="*[name()=$select_sort_field]" /> --> ----------------------------------- but that's not working - I keep getting this error: msxml4.dll error '80004005' Keyword xsl:sort may not be used here. ------------------------------------ What am I doing wrong? The thing is, if I take out the entire choose, and just use <xsl:sort select="code" /> or <xsl:sort select="*[name()=$select_sort_field]" /> it seems to work. The thing is, I wanted to make it bullet proof in case the script invoking this style sheet doesn't pass in the $select_sort_field parameter - if not passed in, I want it to sort by "code". TIA. Hardy Merrill.
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