Re: [xsl] Data-driven Display of records with variable number of fields

["Rich Caloggero" <rjc@xxxxxxx>]

Thanx Wendell. This worked out fine!

-- Rich

----- Original Message -----
From: "Wendell Piez" <wapiez@xxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, December 09, 2004 6:46 PM
Subject: Re: [xsl] Data-driven Display of records with variable number of
fields


> Rich,
>
> The usual approach to this is to use the name() or local-name() function
to
> extract the names of your elements as strings, and then do string testing
> against those names in the predicate of an XPath, to select them.
>
> So when your context node is an unknown element type, you can still get
all
> the nodes of that type that are, say, children of some othe node $parent,
> by saying
>
> $parent/*[name()=name(current())]
>
> ... you can even parameterize a name (again as a string) and pass it
around
> between templates.
>
> So let's say you wanted to process a set of $records ... you could say
>
> <xsl:for-each select="$records">
>    <xsl:variable name="thisrecord" select=".">
>    <xsl:for-each select="/headers/*">
>      <xsl:apply-templates
>        select="$thisrecord/*[local-name()=local-name(current())]"/>
>    </xsl:for-each>
> </xsl:for-each>
>
> ... which applies templates only to the children of each member of
$records
> whose names appear as the name of an element child of /headers, in the
> order they appear there. (In this example I used the local-name() function
> so you could keep your elements in separate namespaces if you wanted.)
>
> I hope this is enough to get you going.
>
> Cheers,
> Wendell
>
> At 04:05 PM 12/9/2004, you wrote:
> >Is this possible in xslt-1.0?
> >
> >Given the following input, I want to transform the output such that I get
> >only the fields of each record which I specify in the headers element. I
> >want the order to also be the order in which they appear in the headers
> >element.  So if headers looks like:
> ><headers>
> ><year/> <artist/>
> ></headers>
> >then I want each record in the output to only contain the year and artist
> >fields, in that order.
> >
> >I can't seem to write an xPath expression for this kind of transform
because
> >xPath node tests cannot contain variables. The expression would need to
look
> >something like "/cds/cd/$field", where $field would contain the name of
one
> >of the nodes listen in /headers (see xml below).
> >
> >Thanx for any suggestions...
> >
> >-- Rich
> >
> >Input:
> ><?xml version="1.0" encoding="ISO-8859-1" ?>
> ><?xml-stylesheet type="text/xsl" href="transform.xsl"?><cds>
> ><title>My CD Collection</title>
> ><headers>
> ><title/>
> ><artist/>
> ><year/>
> ></headers>
> >
> ><cd>
> ><artist>Rich Caloggero</artist>
> ><title>A Taste of Tranquility</title>
> ><year>2004</year>
> ><label>Touch the Sky Music</label>
> ></cd>
> >
> ><cd>
> ><artist>The Grateful Dead</artist>
> ><title>Europe 72</title>
> ><year>1972</year>
> ></cd>
> ></cds>
> >
> >
> >
> >-- Rich
> >"In the end, our society will be defined not only by what we create, but
by
> >what we refuse to destroy."
> >-John C. Sawbill (1936-2000), president, The Nature Conservancy,
1990-2000
>
>
> ======================================================================
> Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
> Mulberry Technologies, Inc.                http://www.mulberrytech.com
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