Subject: RE: [xsl] Equivalence between XSL and XPath expression From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sat, 11 Dec 2004 00:26:20 -0000 |
> How can the XPath return 0, if has a context node (.) and has > the self > axis in ancestor-or-self? This way it has to return at least 1! I think you are assuming the context node is a menu element. There's no reason to assume that. If the context node is the root (document) node (for example) the XPath expression will return 0. Michael Kay http://www.saxonica.com/ > > > Michael Kay wrote: > > >>And the question is: Is this XPath expression > >> > >>count(./ancestor-or-self::menu)+count(./preceding::menu) > >> > >>equivalent to this XSL expression? > >> > >> <xsl:variable name="position"> > >> <xsl:number level='any' count="menu"/> > >> </xsl:variable> > >> > >> > >> > > > >Almost. xsl:number will never return 0, but the XPath > expression might. Take > >a look at the XSLT 2.0 spec which defines xsl:number in > terms of equivalent > >XPath expressions. > > > >Michael Kay > >http://www.saxonica.com/
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