Subject: [xsl] Conditional selecting From: "Jim Neff" <jneff@xxxxxxxxxxxxxxx> Date: Mon, 13 Dec 2004 12:20:33 -0500 |
Greetings, Here is my XML document: <record type="EA0"> <field_no>46</field_no> <starting_position>267</starting_position> <length>8</length> <justification>L</justification> <content></content> <default_value></default_value> <data_type>text</data_type> </record> <record type="EA0"> <field_no>47</field_no> <starting_position>275</starting_position> <length>8</length> <justification>L</justification> <content>CLM_CR_DT</content> <default_value></default_value> <data_type>date2</data_type> </record> <record> <record type="EA0"> <field_no>47</field_no> <plan_id>CHNCT</plan_id> <starting_position>275</starting_position> <length>8</length> <justification>L</justification> <content>claim_paid_date</content> <default_value></default_value> <data_type>date2</data_type> </record> <record type="EA0"> <field_no>48</field_no> <starting_position>283</starting_position> <length>1</length> <justification>L</justification> <content></content> <default_value></default_value> <data_type>text</data_type> </record> Here is a snip of the XSL stylesheet that uses this : <xsl:apply-templates select="$field_definitions/*[@type = 'EA0']"> <!-- number() makes sure we process field_no as a number and not a string, otherwise 11 comes before 9 ;) --> <xsl:sort select="number(field_no)" order="ascending"/> <xsl:with-param name="current_context" select="."/> </xsl:apply-templates> I select those records that match the "EA0" record type and then sort them according to field_no. My question is in regards to field_no 47. What I want to do is select the record IF there is a plan_id instead of the record without a plan id. Not all records will have a plan id. So if there is a child element of the record node that has a value in the plan_id field then use that record number instead of the record with the same number that DOES NOT have the plan_id. Thanks in advance, Jim Neff
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