Subject: RE: [xsl] sum() function giving strange result From: <Jarno.Elovirta@xxxxxxxxx> Date: Tue, 14 Dec 2004 08:34:45 +0200 |
Hi, > The sum funciton is giving some strange result. > > Xml :- > <documents> > <value>10.11</value> > <value>20.22</value> > <value>30.33</value> > <value>40.44</value> > <value>50.55</value> > <value>10.11</value> > <value>20.22</value> > </documents> > > XSL :- > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:exsl="urn:schemas-microsoft-com:xslt" > extension-element-prefixes="exsl"> > > <xsl:variable name="SubTotals"> > <xsl:for-each select="/documents/value"> > <value><xsl:value-of select="." /></value> > </xsl:for-each> > </xsl:variable> > > <xsl:template match="/"> > <xsl:apply-templates select="documents/value" /> > </xsl:template> > > <xsl:template match="value"> > <xsl:variable name="Position" select="position()" /> > <xsl:value-of > select="sum(exsl:node-set($SubTotals)/value[position() > < $Position])" /><br /> > </xsl:template> > > </xsl:stylesheet> > > > The result :- > 0 > 10.11 > 30.33 > 60.66 > 101.1 > 151.64999999999998 > 161.76 > > I am worried about the output 151.64999999999998. Why is it > outputting this > value? Because XPath uses a floating-point numbers <http://www.w3.org/TR/xpath#numbers>. > I am expecting to be upto 2 decimal places or 1 decimal places. > > Well I can mask it upto 2 decimal places but I do not have a > liberty to do > that. How about <xsl:variable name="SubTotals"> <xsl:for-each select="/documents/value"> <value> <xsl:value-of select=". * 100" /> </value> </xsl:for-each> </xsl:variable> ... <xsl:template match="value"> <xsl:variable name="Position" select="position()" /> <xsl:value-of select="sum(exsl:node-set($SubTotals)/value[position() < $Position]) div 100" /> <br /> </xsl:template> Seems to give the expecter result. 0 10.11 30.33 60.66 101.1 151.65 161.76 Cheers, Jarno
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