Subject: [xsl] convert a url path to an xpath From: "Lincoln Mitchell" <lincoln@xxxxxxxxxxx> Date: Thu, 30 Dec 2004 10:33:53 +0800 |
I have a path like www.domain.com/company/about/staff.htm and match "company/about/staff" in the sitemap. However, I cannot use this path directly in my xpath expression as the xml looks like: ... <wx:sub-section> <w:p> <w:r> <w:t>company</w:t> </w:r> </w:p> ... <wx:sub-section> <w:p> <w:r> <w:t>about</w:t> </w:r> </w:p> ... <wx:sub-section> <w:p> <w:r> <w:t>staff</w:t> </w:r> </w:p> ... ... So, somehow I need to create a xpath from the path "company/about/staff" that looks like: "wx:sub-section[w:p/w:r/w:t='company']/wx:sub-section[w:p/w:r/w:t='about']/w x:sub-section[w:p/w:r/w:t='company']" But how? Any help greatly appreciated. Linc
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] Displaying Base64Binary , Lincoln Mitchell | Thread | Re: [xsl] convert a url path to an , M. David Peterson |
[xsl] Displaying Base64Binary as I, Walid koleilat | Date | Re: [xsl] convert a url path to an , M. David Peterson |
Month |