Subject: RE: [xsl] Selecting an attribute value from a variable From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 7 Jan 2005 09:58:00 -0000 |
Variables hold values, not XPath expressions. Many processors have a dyn:evaluate() extension that allows you to construct and evaluate an XPath expression dynamically, but you don't need it here. Use @*[name()=$var] Incidentally, it's poor practice to represent information by means of a sub-syntax within element and attribute names. You should be using child elements of the form <LastId Page="1">12</LastId> But we all sometimes need to deal with badly-designed XML. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Chris Hicks [mailto:chrish2000@xxxxxxxxxxxxxx] > Sent: 07 January 2005 09:19 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Selecting an attribute value from a variable > > Hi, > > I'm building a variable in xslt like this: > > <xsl:variable name="previouspagelastid" > select="concat('@Page',string(@pageNumber - 1),'LastID')"/> > > To refer to an attribute in an xml node that I know exists > (@Page1LastID for > example). > > The root node of my template match looks like this: > > <results pageNumber="2" pageCount="3" pageSize="10" resultCount="30" > criteria="" Page1LastID="12" Page2LastID="" Page3LastID="" > Page4LastID="" > Page5LastID="" Page6LastID=""> > > I'm not sure if its possible but after I declare this > variable I want to get > its value, ie. "12" > > Any ideas? > > Cheers, > > Chris
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