[xsl] namespace-alias question

[omprakash.v@xxxxxxxxxxxxx]

Hi,
    Iam using XSL to transform a schema into xsl and it is causing many
problems.
My stylesheet looks like this:

Here Iam using x to prefix my stylesheet while using xsl to prefix the
stylesheet being outputted
as suggested by Steve Muench.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xmlns:x
="http://tempuri";
xmlns:xsd="http://www.omprakashv.org"; version="1.0">

<x:namespace-alias stylesheet-prefix="x" result-prefix="xsl"/>

In order to output the <xsl:stylesheet> element in to the output I have
tried many ways like below:

<x:text disable-output-escaping="yes">
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform";?
</x:text>

<x:text disable-output-escaping="yes">
&#60;xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform"&#62;
</x:text>

While the above compiles, the result of the transformation is empty
document using both oracle xsl parser and xalan.

The other way suggested by many doesnt work with the xslt processors.

<x:template match="xsd:schema">
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform";?
</x:template>


Any suggestions would be appreciated.

Regards,
Omprakash.V







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