Subject: Re: [xsl] Comparing node for identity using union From: António Mota <amsmota@xxxxxxxxx> Date: Wed, 19 Jan 2005 16:24:46 +0000 |
Does the fact that i'm setting this parameter from Javascript/Sarissa change your remark? I'm testing it now but it's too much confusing and i don't have the time to figure it out. But it seems there are different beahviours in the way i pass the parameter. Firstly i had pos = 1 //or whatever Sarissa.setXslParameter(xslDoc, "pos", pos+""); xml.transformNodeToObject(xslDoc, xmlResult); because with Sarissa.setXslParameter(xslDoc, "pos", pos); was giving a error (now does not give a error but gets thw wrong result) So when i change the code to use ths XSLTProcessor i used the same processor.setParameter(null, "pos", pos+""); var xmlResult = processor.transformToDocument(xmlDoc); that gives the wrong behaviour. But if i use processor.setParameter(null, "pos", pos); it works OK. So they have the opposite functioning. When i use oXygen i get many problems when setting the params, so i simply change the declaration <xsl:param name="pos" select="1"/> or wathever number i want, and worked ok every time with the diferent processors. So i'm so confused now that i just want to ask a simple question. When i set a parameter defined like <xsl:param name="pos" select="0"/> outside the XSLT does the parameter stays a number, changes to char, it depends on the processor, or what? On Wed, 19 Jan 2005 14:00:49 -0000, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > The $pos is defined like > > > > <xsl:param name="pos" select="0"/> > > That's certainly a number, and since positions start at 1, xyz[$pos] should > always be an empty sequence (node-set). If, as you say, one processor is > behaving differently from all the others, then that's prima facie evidence > of a bug. > > Michael Kay > http://www.saxonica.com/
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