RE: [xsl] How can I conditionaly assign a node-set to my variable ?

[Pieter Reint Siegers Kort <pieter.siegers@xxxxxxxxxxx>]

Hi Roy,

Have you tried to insert spaces in 6>$n --> 6 > $n? I count another 4
times. You do it correctly with 'and' and 'or'.

HTH,
<prs/>

-----Original Message-----
From: r.moe@xxxxxxxxxxxxxxxxxx [mailto:r.moe@xxxxxxxxxxxxxxxxxx]
Sent: Miircoles, 19 de Enero de 2005 12:13 p.m.
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] How can I conditionaly assign a node-set to my variable?

How can I conditionaly assign a node-set to my variable?
Variable needs to have local scope.
Obviously I can't use <xsl:value-of.../>.
I get the error message:
"Reference to variable or parameter 'firstTableRows' must evaluate to a node
list."

Code:

<xsl:variable name="firstTableRows">
 <xsl:choose>
   <xsl:when test="6&gt;$n and $hasP">
     <xsl:value-of select="channel[6&gt;id or id='P']"/>
   </xsl:when>
   <xsl:when test="6&gt;$n">
     <xsl:value-of select="channel[6&gt;id]"/>
   </xsl:when>
   <xsl:otherwise>
     <xsl:value-of select="channel[6&gt;id]"/>
   </xsl:otherwise>
 </xsl:choose>
</xsl:variable>

Thanks,
Roy