RE: [xsl] Reading the XML declaration using XSL

[<Jarno.Elovirta@xxxxxxxxx>]

Hi,

>     I'd like to change the way an XML file gets rendered in a browser.
> The effect that I want to achieve is what Mozilla does when one does a
> "View source" - i.e. displays the XML as a text document with syntax
> highlighting. I can write an XSL program to read XML and produce
> syntax highlighted output, and associate the XSL to the XML via the
> xml-stylesheet PI. However, if the XML file that I'm processing has an
> XML declaration at the top, then I'm at a loss as to how to process
> that. I've been unable to figure out a way to use XSL to read the XML
> declaration and process that. Any ideas / suggestions?

XPath source tree doesn't contain information about the document that was used
to generate the tree (well, basedir is there but you can't access it). This
applies to encoding too. A feature of XPath & XSLT.

Cheers,

Jarno