Subject: Re: [xsl] finding nodes From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 24 Jan 2005 14:01:50 GMT |
<xsl:variable name="nset"> <xsl:copy-of select="/campus[@name = $value]"/> </xsl:variable> as has been said already in thi sthread, don't (ever) do that, which generates a result tree fragment (and is expensive even in XSLt2 where it would generate a node set) do <xsl:variable name="nset" select="/campus[@name = $value]"/> However there will only be one element node below / so thi snode set will have at most one element in it, depending on whether the top level element is a campus element with that attribute. Is that really what you want? and then define the template match = "campus". But wouldn't <xsl:template match="campus"> match other campus nodes as well. It would match, but unless you apply templates to those other nodes, they would never be processed. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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