Subject: Re: [xsl] traversing xsl using xsl From: omprakash.v@xxxxxxxxxxxxx Date: Fri, 4 Feb 2005 13:32:32 +0530 |
Hi, This should get you started. But if I were you I would only proceed with this approach if I should absolutely must. Just make sure you change the xforms namespace to the right one below. Regards, Omprakash.V <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xforms="xforms ns here" version="1.0"> <xsl:copy> <xsl:copy-of select="/"/> </xsl:copy> <xsl:template match="xsl:template"> <xsl:message>match = template<xsl:value-of select="name(.)"/></xsl:message> <xsl:apply-templates select="*"/> </xsl:template> <xsl:template match="xsl:apply-templates"> <xsl:message>match = apply-template<xsl:value-of select="name (.)"/></xsl:message> </xsl:template> <xsl:template match="xsl:value-of"> <xsl:message>match = value-of<xsl:value-of select="name(.)"/></xsl:message> </xsl:template> <xsl:template match="xsl:attribute"> <xsl:message>match = attribute<xsl:value-of select="name (.)"/></xsl:message> </xsl:template> <xsl:template match="xsl:if"> <xsl:message>match = if<xsl:value-of select="text()"/></xsl:message> <xsl:apply-templates select="*"/> </xsl:template> <xsl:template match="xforms:input"> <input> <xsl:attribute name="type"> <xsl:value-of select="text"/> </xsl:attribute> <xsl:attribute name="name"> <xsl:value-of select="fname"/> </xsl:attribute> </input> </xsl:template> </xsl:stylesheet> "Prasad Akella" To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <avlnprasad@w cc: (bcc: omprakash.v/Polaris) eb.de> Subject: [xsl] traversing xsl using xsl 02/04/2005 01:58 AM Please respond to xsl-list hi, I am stuck with the problem of traversing an xsl file using another xsl. I was suggested to take the output of my xsl file1 and use it in xsl file2 but have not been able to do so. My xsl file1 transforms an xml document into xforms I would like to write xsl file2 which takes or is called in xsl file1 and the output is xhtml instead of xforms which i intend to do by matching all tags and substituting with adequate transformations. Please let me know how this is possible. If i import my xsl file1 into xsl file2 my second file is not doing anything and the vice versa is also not working and my xsl file1 is rendering normal xforms eventhough i call my xsl file2. The point is that the transformation in xsl file1 has to be bypassed and subsituted by xsl file2 transformation. with regards, prasad Akella ______________________________________________________________ Verschicken Sie romantische, coole und witzige Bilder per SMS! Jetzt bei WEB.DE FreeMail: http://f.web.de/?mc=021193 This e-Mail may contain proprietary and confidential information and is sent for the intended recipient(s) only. If by an addressing or transmission error this mail has been misdirected to you, you are requested to delete this mail immediately. You are also hereby notified that any use, any form of reproduction, dissemination, copying, disclosure, modification, distribution and/or publication of this e-mail message, contents or its attachment other than by its intended recipient/s is strictly prohibited. Visit Us at http://www.polaris.co.in
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