Subject: [xsl] example for xsl:output saxon:next-in-chain From: <uap001@xxxxxxxxx> Date: Thu, 10 Feb 2005 05:10:10 -0800 (PST) |
Hello, I am trying to use the "xsl:output saxon:next-in-chain" in a xslt file where I need to pass the output from one xsl file to the next xsl file to generate the final output. But, I am not able to make it work. It just gives me the final output which is same as the first xsl translation. Following is my xslt file : <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:saxon="http://icl.com/saxon" version="1.0"> <xsl:import href="first.xsl"/> <xsl:output method="xml" indent="yes" saxon:next-in-chain="second.xsl"/> </xsl:stylesheet> With this xslt file, I only get the final output which is the one coming out by applying first.xml. It doesn't seem to be applying the second.xsl translation. Not sure what I am doing wrong here. What I want to do is translate my.xml to final.xml as follow : my.xml -> translate with first.xml -> firstoutput.xml -> second.xml -> finaloutput.xml I don't want the intermediate firstoutput.xml - I only want the finaloutput.xml. - ana __________________________________ Do you Yahoo!? All your favorites on one personal page Try My Yahoo! http://my.yahoo.com
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