Subject: Re: [xsl] Transformation of From: "Richard Lewis" <richardlewis@xxxxxxxxxxxxxx> Date: Fri, 11 Feb 2005 11:30:21 +0000 |
Couldn't you have something like: <xsl:template match="item[contains(text(),'%')]"> On Fri, 11 Feb 2005 12:20:41 +0100, news@xxxxxxxxxxx said: > Hello List, > > I have the following XML in form of a variable: > > input: > <XML> > <item>vlue</item> > <item>%special value%</item> > <item>vlue</item> > <item>%special value%</item> > <unkown_items/> > <unkown_items/> > </XML> > > I want to transform the variable into another variable, having all > <item>s > values which contain a '%' changed into other values. (like "super > special > value" instead of "%special value%") > My problem is, that there are planty of unknown items in the variable > that I > dont know and that might change. But I want the XML structure to stay as > it > is, and just replace some items values. > > output: > <XML> > <item>vlue</item> > <item>super special value</item> > <item>vlue</item> > <item>super special value</item> > <unkown_items/> > <unkown_items/> > </XML> > > How can I do this? > > thanks! > > Jan
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