Subject: [xsl] RE: Display children of node with given Id!! From: "Adam J Knight" <adam@xxxxxxxxxxxxxxxxx> Date: Wed, 16 Feb 2005 20:07:50 +1000 |
Hi all, Following on from my previous post. Thanks to those who replied, it is much appreciated. This stylesheet matches all nodes that are descended from node with a given id. Two Things: 1) How do I modify this stylesheet to include the rendering of all top level tree nodes? Can I do this in the <xsl:apply-templates select=""/> element. I have tried <xsl:apply-templates select="parent::tree or //tree_node[@id = $id]"/>??? 2) How do I modify this stylesheet to only display immediate children(not grandchildren ect) descended from the node with a given id. In the case node id = 7 , nodes 8, 9 will only be displayed. Not 10. COMPLETE XML STRUCTURE: <tree> <tree_node id="7" value="Test"> <tree_node id="8" value="Test Sub"/> <tree_node id="9" value="Test Sub One"> <tree_node id="10" value="Test Sub Two"/> </tree_node> </tree_node> <tree_node id="11" value="Test 2"/> </tree> COMPLETE XSL FILE: <?xml version="1.0"?> <xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="css"/> <xsl:param name="url"/> <xsl:param name="id"/> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <table cellspacing="0" cellpadding="2" class="{$css}"> <tr> <td class="ui_tree_bar"> <a href="{$url}&action=add">add</a> </td> </tr> <xsl:apply-templates select="//tree_node[@id=$id]"/> </table> </xsl:template> <xsl:template match="tree_node"> <tr> <td> <table width="100%"> <tr> <td align="right" width="{count(ancestor-or-self::*) * 10}"> <a href="{$url}&node={@id}">+</a> </td> <td> <xsl:value-of select="@value"/> </td> <td width="25%"> <a href="{$url}&action=edit&node={@id}">edit</a> <a href="{$url}&action=delete&node={@id}">delete</a> </td> </tr> </table> </td> </tr> <xsl:apply-templates/> </xsl:template> </xsl:stylesheet> Cheers, Adam NB: "Pray as if everything depended upon God and work as if everything depended upon man."
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