Subject: [xsl] xslt to generate XSL-FO table-layout=fixed From: "Ilya Sterin" <ilya@xxxxxxxxxxx> Date: Mon, 21 Feb 2005 14:19:37 -0500 |
Hello, I currently have an XSLT that transforms XML to XSL-FO. We're using FOP as the engine. Since FOP only supports table-layout="fixed", I'm in a small bind. The XSLT transforms regular XHTML tables to XSL-FO tables. Since in HTML we don't know how many columns the table will hold before hand, I can't seem to figure out a way to generate a fixed table layout in FO, since I'm not sure how many fo:table-column elements will be present in each table. Has anyone ever come up with a solution for something similar. I googled for some XSLT/XPath way of solving this, and most solutions lead to having a columns="#" attribute in the table element. Since we can't enforce this, is there another way of possibly counting the columns in say the first row, to generate the fo:table-column elements? What's the most elegant way of resolving this? Thanks in advance for any help. Ilya
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