Subject: RE: [xsl] Common Element Solution (XSL 2.0) From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 23 Mar 2005 09:00:33 -0000 |
> -----Original Message----- > From: Pawson, David [mailto:David.Pawson@xxxxxxxxxxx] > Sent: 23 March 2005 08:24 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > you want something like > > count(current-group()/parent::table) = $number-of-tables > > relying on the fact that "/" eliminates duplicates. > > That last line has me puzzled Mike. Would someone expand please, > for the uninitiated? In the input we have a set of tables each containing zero or more columns, each column has a name. We want to find the names of the columns that appear in each table. Group the columns by name; for each group (of columns with the same name), the column appears in every table if the number of tables containing a column in that group equals the total number of tables. Any clearer? Michael Kay http://www.saxonica.com/
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