[xsl] Re: Convert a XML string to a node

Subject: [xsl] Re: Convert a XML string to a node
From: António Mota <amsmota@xxxxxxxxx>
Date: Wed, 23 Mar 2005 10:21:47 +0000
Well, let me add some info. I have this xsl:

	<xsl:param name="nnode" select="/.."/>

	<xsl:template match="/*">
		<xsl:copy>
			<xsl:apply-templates/>
			<xsl:copy-of select="$nnode"/>
		</xsl:copy>
	</xsl:template>

	<xsl:template match="node()|@*">
		<xsl:copy>
			<xsl:apply-templates select="@*|node()"/>
		</xsl:copy>
	</xsl:template>

and what i wish to acomplish is to insert at the root level any tree
structure that's passed to the param (polimorphism, how i like that
word!).

Since it seems i can't do that on FF, i was thinking in some sort of
alternative, maybe using some kind of document() or some xsl template
that parse the node tags in a string containing the xml and creating
the output nodes or whatever...

I'm a bit frustated with all this effort i'm putting in making my apps
cross-browser, at least to IE and FF, but sometimes it seems it's too
much overhead in it. Maybe i just give up, sold my soul to the forces
of darkness and use only IE...



On Tue, 22 Mar 2005 23:12:16 +0000, Antsnio Mota <amsmota@xxxxxxxxx> wrote:
> I have this situation where i'm creating a DOM doc in Javascript and
> adding some nodes to it, that i want to pass to a param in a XSLT.
>
> It works ok in IE, but it seems not in FF
> (https://bugzilla.mozilla.org/show_bug.cgi?id=248025)
>
> So can i pass this as a string instead and converting it to a node so
> i can include it in my result tree?
>
> Since i'm working on the browser i can't use extensions, so it seems
> i'm on a dead end in  here.
>
> Does someone have any thoughts?
>
> Thanks.

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