Subject: Re: [xsl] in this xsl , why dont get result with substring-before .. From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Fri, 25 Mar 2005 13:44:56 -0000 |
Problem number 1)i have this two files. when i try to get with substring-before or substring-after i get no data
Problem number 2) why i get in this for-each loop only one time the content of workstep1 node
Again the holiday mood has taken over, Can you clarify what you want to achieve?Problem number 3) what is the other alternativity to call a template in this loop instead of to use xsl:apply-templates ? thanks
<?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template match="/Job"> <html><head><META http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
</head><body>
<table> <tr> <td></td> <td> <b>JOB Desc. </b></td></tr>
<xsl:for-each select="Jobsdetails"> <tr> <td></td> <td> <xsl:value-of select="jobDescription"/></td>
</tr>
<xsl:apply-templates select="worksPart1"/> </xsl:for-each> </table></body></html>
</xsl:template>
<xsl:template match="worksPart1" > <tr> <td></td> <td> <xsl:if test="contains(bbb,'RRR')"> <xsl:value-of select="substring-before('bbb','RRR')"/> +<xsl:value-of select="substring-after('bbb','RRR')"/> </xsl:if> </td>
</tr>
</xsl:template> </xsl:stylesheet>
------------------------------------------ <?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="test.xsl"?> <Job>
<Jobsdetails> <jobDescription>mydescription</jobDescription> <worksPart1>
<bbb>beforeRRRafter</bbb> <worksNr>20362</worksNr>
</worksPart1> </Jobsdetails> </Job>
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] in this xsl , why dont get re, henry human | Thread | Re: [xsl] Attribute List, Mukul Gandhi |
[xsl] in this xsl , why dont get re, henry human | Date | Fwd: Re: [xsl] XSLT in JDK1.5 from , Wendell Piez |
Month |