Subject: RE: [xsl] (newby) define an attribute based on an attribute value From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 1 Apr 2005 09:39:37 +0100 |
As well as the answer to your question (A[...]/B/@v) you might like to note that you don't have to use xsl:element and xsl:attribute. You can write the much more concise <Point PointAttribute="{A[@id='123']/B/@v}"/> XSLT has a reputation for verbosity, but it doesn't have to be as bad as people sometimes make it. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: dalloro@xxxxxxxxx [mailto:dalloro@xxxxxxxxx] > Sent: 01 April 2005 08:22 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] (newby) define an attribute based on an attribute value > > Hi, > > I'm a newby in XSL tranformations. I need to trasform an XML file into > another XML file with a different structure. > > Inside a template I build an element named Point that has several > attributes. The value of one of these attributes depends on the value > of an attribute in the source XML (the attribute v of the element B > that I filtered through the parent 'id', in the code below) > > [snip] > <xsl:element name="Point"> > [snip] > <xsl:attribute name="PointAttribute"> > <xsl:value-of select="A[@id='123']/B[@v]"/> > </xsl:attribute> > [snip] > </xsl:element> > [snip] > > I would like to obtain a 'Point' element with an attribute called > 'PointAttribute' with the same value of the 'v' attribute of the > element 'B'. > > What is the best way to deal with this problem? > > I thank you for the help. > Best regards. > > Livio.
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] (newby) define an attribute b, dalloro | Thread | Re: [xsl] (newby) define an attribu, dalloro |
RE: [xsl] namespace value output at, Michael Kay | Date | Re: [xsl] (newby) define an attribu, dalloro |
Month |