[xsl] namespaces in xslt

Subject: [xsl] namespaces in xslt
From: omprakash.v@xxxxxxxxxxxxx
Date: Fri, 1 Apr 2005 17:24:07 +0530
Hi,
        Iam having diffculty following what's happening:

I have xml like this

<table>
<th>
<root>
<tr>
<slideshow xmlns="urn:hl7-org/v3" title="Sample Slide Show" date="Date of
publication" author="Yours Truly">
<td><a href="file:///N65538"/>
</td>
</slideshow>
</tr>
</root>
</th>
</table>


And my xsl:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform"; xmlns="urn:hl7-org/v3" >

<xsl:output method="xml" indent="yes" />

   <xsl:template match="/">

     <xsl:for-each select="//root/*[1]">
     <xsl:copy>
     <xsl:copy-of select="@*"/>
<xsl:apply-templates select="@*|node()">
          <xsl:with-param name="rootnode" select="$rootnode"/>
     </xsl:apply-templates>
     </xsl:copy>
     </xsl:for-each>
   </xsl:template>

</xsl:stylesheet>


When I select //own:root/*[1] in the <xsl:for-each>,  I get the following

<?xml version="1.0" encoding="UTF-8"?>
<tr xmlns="http://XYZ"/>

but when I make it //root/*[2], I get nothing. But if you see, the
slideshow is really at position 2 so I need to use 2.


Cheers,
Omprakash.V




















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