Subject: [xsl] Select nodes with equal position From: Norbert Heidbrink <nh@xxxxxxxx> Date: Sat, 2 Apr 2005 20:28:34 +0200 |
Hallo everyone, depending on the postion() of a certain node I would like to select another node with the same position. It works if I invent a variable. But I wonder if there is a way to do it without the use of a variable? XML: <table> <colspec colname="c1"/> <colspec colname="c2"/> <colspec colname="c3"/> <row> <entry colname="c1">r1_1</entry> <entry colname="c2">r1_2</entry> <entry colname="c3">r1_2</entry> </row> </table> XSL: <xsl:template match="entry"> <xsl:variable name="mypos"> <xsl:value-of select="position()"/> </xsl:variable> <xsl:value-of select="../../colspec[position() = $mypos]/@colname"/> </xsl:template> Best regards and thanks for your comments, Norbert Heidbrink
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