[xsl] adding namespaces to result nodes

[omprakash.v@xxxxxxxxxxxxx]

Hi,

        Iam using <xsl:for-each select="namespace:*"> to iterate over all
namespace attributes on the input element and write them to the result.
using <xsl:value-of select=name(.)"/> and <xsl:value-of select=."/>.


Now when I do an inverse transform in an effort to recreate the original
xml, my xml comes out like this. I still haven't managed to get the schema
namespace in my result probably because the xmlns:xsl is treated as a
namespace and xsi:schemaLocation as an attribute.

<?xml version="1.0" encoding="UTF-8"?>
<ns0:slideshow xmlns:ns0="urn:hl7-org/v3" a_title="Sample Slide Show"
author="Yours Truly" date="Date of publication"/>
<ns1:slide xmlns:ns1="urn:hl7-org/v3"/>
<title/>
<ns2:slide xmlns:ns2="urn:hl7-org/v3"/>
<title/>
<item/>

My original xml I started out with looked as follows:

<?xml version='1.0' encoding='utf-8'?>

<slideshow xmlns="urn:hl7-org/v3" xmlns:xsi
="http://www.w3.org/2001/XMLSchema-instance";
  xsi:schemaLocation="http://tiling.org/xmlcatalogs/namespaces/recipe
    http://tiling.org/xmlcatalogs/schemas/recipe.xsd"; a_title="Sample Slide
Show"
    date="Date of publication"
    author="Yours Truly">

    <slide type="all">
      <title>Wake up to WonderWidgets!</title>
    </slide>

Iam using DC's suggestion to create elements in the right namespace as
follows:

<xsl:element name="{$elemname}" namespace="{$nsname}">


As you can see the inverse transformed output has prefixes where my
original had none. Also, the prefixes are numbered like ns0, ns1 etc. which
I don't think is not correct. Ideally, I would like for my result to look
exactly or as close to the original as possible. Could someone explain how
to attach multiple namespace nodes like xmlns, xmlns:xsi etc to my element.


Cheers,
Omprakash.V


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