Subject: Re: [xsl] list of actual attributes? From: Per Jessen <per@xxxxxxxxxxxx> Date: Fri, 08 Apr 2005 12:10:29 +0200 |
David Carlisle wrote: >> I could have used <xsl:copy> instead of <xsl:element name="{name()}">, but I don't see what >> I'd gain. (perhaps someone can explain?) > > you get a potentially different result. [thanks for the explanation, snipped] >> Anyway, the problem I'm experiencing is - the list of attributes that I get using '@*' seems >> to also include the attributes with default values from the DTD. How do I get the list of >> actual attributes as used in the source document? > > You don't. The attributes are added by the DTD by the XML parser before > XSLT starts and XSLT has no record of the difference. The whole point of > attribute defaults are to _save_ later applications having to special > case code for attributes being there or not being there, by normalising > things so they are always there. If the non-appearence of an attribute > has a significance then the DTD should mark it as #IMPLIED rather than > supplying a default, to allow an application such as XSLt to "imply" > some default behaviour. OK, that makes sense. > I dont't know xalanc but in many systems it is possible to supply an > entity resolver or catalogue to customise how dtds and other files are > fetched, if that is possible here you could arrange things so an empty > dtd was supplied when the transform was made so teh dtd defaults did not > happen. Yes, xalanc has the same feature - in fact I am already using a custom-written resolver, so I'll try this out right away. /Per Jessen, Z|rich -- http://www.spamchek.co.uk/freetrial - anti-spam and anti-virus services in 30 minutes.
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