|
Subject: [xsl] grouping, sorting, splitting From: beowulf <carisenda@xxxxxxxxx> Date: Mon, 18 Apr 2005 11:12:25 +0100 |
Hi,
I have XML if the form:
<page>
<entry date="2005-04-15">
<title>foo</title>
</entry>
<entry date="2005-04-15">
<title>bar</title>
</entry>
<entry date="2005-02-05">
<title>baz</title>
</entry>
...
</page>
Which I am trying to group by date, sort by tiltle and then split into
sets of 3, 3 being the number of columns in the HTML TABLE element I
am trying to produce as an end result.
I've got the grouping and sorting:
<xsl:for-each select="entry[key('days', @date) and count(.|key('days',
@date)[1])= 1]">
<xsl:sort select="title"/>
and I've even got the first item in each group of three from that
grouped and sorted set:
<xsl:for-each select="key('days', @date)[position() mod 3 = 1]">
But I just can't seem to make the final leap to displaying the
following siblings of the above, making the 3 cell rows. Should I be
doing this some other way or can someone help me where I am?
Many thanks,
Stephen
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| RE: [xsl] xsl sort: using element a, Michael Kay | Thread | Re: [xsl] grouping, sorting, splitt, David Carlisle |
| RE: RE: RE: RE: [xsl] GMT to BST co, tom tom | Date | Re: [xsl] grouping, sorting, splitt, David Carlisle |
| Month |