[xsl] default namespace error in xalan

Subject: [xsl] default namespace error in xalan
From: omprakash.v@xxxxxxxxxxxxx
Date: Wed, 20 Apr 2005 15:49:42 +0530
Hi,
      I have a stylesheet with a number of namespace declarations in the
stylesheet element like so:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                   version="1.0"
                   xmlns:xalan="http://xml.apache.org/xalan";
                   xmlns:xsd="schema ns"
             xmlns:prefix=" foo namespace"
             xmlns:acord-doc=" adoc namespace"
             xmlns:jag=" jag namespace"
                  xmlns=" no namespace "
             exclude-result-prefixes="xalan"
             >

<xsl:strip-space elements="*"/>

<xsl:output method="xml" indent="yes" />

<xsl:template match="/">
 <xsd:schema>
</xsd:schema>

</xsl:template>
</xsl:stylesheet>


However, the above stylesheet does not compile and throws the error "Could
not locate the translet class "xamp" where xamp.xsl is the name of the
stylesheet file. Iam using Xalan from the jar shipped with JAXP-1.3.

The stylesheet  works if I remove the line
                  xmlns=" no namespace " from the "xsl:stylesheet"
element.


Cheers,
Omprakash.V








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