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Subject: Re: [xsl] Print number of chars depending upon int value From: Eric van der Vlist <vdv@xxxxxxxxxxxx> Date: Fri, 22 Apr 2005 12:52:41 +0200 |
On ven, 2005-04-22 at 03:47 -0700, Ranjan K. Baisak wrote: > In a reporting application, I need to print number of > chars e.g. '.'s depending upon some numeric variable. > SO it would be a kind of array of chars. Isn't a string a kind of array of chars ;-) ??? > Any function available for the same? what about substring()? http://www.w3.org/TR/1999/REC-xpath-19991116#function-substring <xsl:value-of select="substring('...................................', 1, $myLength)"/> should do the trick! Eric -- Curious about Relax NG? Read my book online. http://books.xmlschemata.org/relaxng/ ------------------------------------------------------------------------ Eric van der Vlist http://xmlfr.org http://dyomedea.com (ISO) RELAX NG ISBN:0-596-00421-4 http://oreilly.com/catalog/relax (W3C) XML Schema ISBN:0-596-00252-1 http://oreilly.com/catalog/xmlschema ------------------------------------------------------------------------
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