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Subject: RE: [xsl] Print number of chars depending upon int value From: "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> Date: Fri, 22 Apr 2005 04:30:13 -0700 (PDT) |
:( facing lots of difficulties for xslt 1.0. Should not there be an alternative for any function in xslt2.0 in xslt 1.0. Otherwise it is required to write 100 lines of code as mentioned by Eliot Harold. -Ranjan --- Michael Kay <mike@xxxxxxxxxxxx> wrote: > > In a reporting application, I need to print number > of > > chars e.g. '.'s depending upon some numeric > variable. > > SO it would be a kind of array of chars. > > > Like many things, it's very easy in 2.0: > > string-join(for $i in 1 to $N return ".", "") > > Michael Kay > http://www.saxonica.com/ > > __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
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