Re: [xsl] order-by vs xsl:sort

[David Carlisle <davidc@xxxxxxxxx>]

let $ci :=count($is) return
let $cj :=count($js) return
for $n in (0 to ($ci * $cj -1)
                           ^^
let $i :=$is[$n  mod $ci)+1]
let $j := $js[($n idiv $ci) +1]
order by f($i, $j)
return
g($i,$j)

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