Subject: Re: [xsl] XPATH total count of multiple child nodes From: Ramkumar Menon <ramkumar.menon@xxxxxxxxx> Date: Tue, 3 May 2005 23:17:24 +0530 |
<xsl:if test="*"> cd do the trick On 5/3/05, Michael Kay <mike@xxxxxxxxxxxx> wrote: > count(*) > > Michael Kay > http://www.saxonica.com/ > > > -----Original Message----- > > From: Edward Bryant [mailto:bryant_edward@xxxxxxxxxxx] > > Sent: 03 May 2005 18:23 > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > Subject: [xsl] XPATH total count of multiple child nodes > > > > > > Thanks everyone for the helpful answers to my previous > > question on character > > entities. > > > > My new problem is that I am trying to build a conditional > > statement based on > > a count of the number of child elements. There is an element > > "dates" that > > contains child elements containing particular dates. > > Normally, I would use > > something like: > > > > Check if any of them exisit at all... > > > > <xsl:if test="(filed) or (decided) or (submitted) or > > (revised) or (term)"> > > > > then, see if there is more than one of them ... > > > > <xsl:if test="count(date) > 1"> > > > > However, the child elements do not all have the same name. > > They can have one > > of five different names (filed, decided, submitted, revised, > > or term), which > > may appear in almost any combination. There are no other > > child elements, so > > I was hoping there was a simple way to count the total number > > of child > > elements without specifying them by name? > > -- Shift to the left, shift to the right! Pop up, push down, byte, byte, byte! -Ramkumar Menon A typical Macroprocessor
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