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Subject: [xsl] <xsl:sort> From: aspsa <aspsa@xxxxxxxxxxxxx> Date: Sat, 07 May 2005 03:37:44 -0400 |
Hi, folks.
I have an XML document which structure is the following:
<document>
<header>
<paragraph>
<subheader>
<paragraph>
.
.
.
<product>
<partname>
<category>
.
.
.
</product>
<product>
<partname>
<category>
.
.
.
</product>
.
.
.
</document>
In a template that matches on "document", I have the following:
<xsl:template match="document">
<xsl:for-each select="child::node()">
// etc...
</xsl:for-each>
</xsl:template>
The XSLT stylesheet works fine, but now I need to sort the "product"
elements based upon the "category" element and in descending order. The
category content is numeric.
How would I execute this from within the "document" template?
Here's what I've tried.
<xsl:template match="document">
<xsl:for-each select="child::node()">
<xsl:if test="product">
<xsl:apply-templates select=".">
<xsl:sort select="category" data-type="number" order="descending" />
</xsl:apply-templates>
</xsl:if>
</xsl:for-each>
</xsl:template>
Where am I going wrong? Thanks for your feedback.
Respectfully,
ASP
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