Subject: [xsl] <xsl:sort> From: aspsa <aspsa@xxxxxxxxxxxxx> Date: Sat, 07 May 2005 03:37:44 -0400 |
Hi, folks. I have an XML document which structure is the following: <document> <header> <paragraph> <subheader> <paragraph> . . . <product> <partname> <category> . . . </product> <product> <partname> <category> . . . </product> . . . </document> In a template that matches on "document", I have the following: <xsl:template match="document"> <xsl:for-each select="child::node()"> // etc... </xsl:for-each> </xsl:template> The XSLT stylesheet works fine, but now I need to sort the "product" elements based upon the "category" element and in descending order. The category content is numeric. How would I execute this from within the "document" template? Here's what I've tried. <xsl:template match="document"> <xsl:for-each select="child::node()"> <xsl:if test="product"> <xsl:apply-templates select="."> <xsl:sort select="category" data-type="number" order="descending" /> </xsl:apply-templates> </xsl:if> </xsl:for-each> </xsl:template> Where am I going wrong? Thanks for your feedback. Respectfully, ASP
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