Subject: RE: [xsl] displaying unique entries in a list From: "Hallas,M" <M.Hallas@xxxxxxxxx> Date: Mon, 9 May 2005 10:40:21 +0100 |
Hi Mukul, Thanks again for providing a fix to my problem. Many thanks, Mike -----Original Message----- From: Mukul Gandhi [mailto:mukul_gandhi@xxxxxxxxx] Sent: 09 May 2005 10:30 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] displaying unique entries in a list I modified the stylesheet as follows.. Its working. <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" /> <xsl:template match="/xml"> <html> <body> <h2>Test example of List output</h2> <hr/> <!--########## Begin Main Document ##########--> <xsl:apply-templates select="List" /> </body> </html> </xsl:template> <!--######## Template for Department Main table data ######--> <xsl:template match="List"> <table border="1" width="100%"> <xsl:apply-templates select="Entry/Department"/> </table> </xsl:template> <!--### Displays first page departments only ###--> <xsl:template match="Entry/Department"> <xsl:if test="not(. = preceding::Department)"> <tr> <td> <span style="color:#000000"> <a href=""><xsl:value-of select="." /></a> </span> </td> </tr> </xsl:if> </xsl:template> </xsl:stylesheet> Regards, Mukul --- "Hallas,M" <M.Hallas@xxxxxxxxx> wrote: > Dear all, > > Hope that you can help with this problem I have > displaying a list of data. > > My XML looks like this: > > <xml> > <List> > <Entry> > <Session>2004/5</Session> > <Department>Accounting and Finance</Department> > </Entry> > <Entry> > <Session>2004/5</Session> > <Department>Accounting and Finance</Department> > </Entry> > <Entry> > <Session>2004/5</Session> > <Department>Maths</Department> > </Entry> > <Entry> > <Session>2004/5</Session> > <Department>Maths</Department> > </Entry> > <Entry> > <Session>2004/5</Session> > <Department>Economic History</Department> > </Entry> > </List> > </xml> > > My xslt example is below: > > <?xml version="1.0" encoding="ISO-8859-1"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:template match="/"> > <html> > <body> > <h2>Test example of List output</h2> > <hr/> > <!--########## Begin Main Document ##########--> > <xsl:apply-templates /> > </body> > </html> > </xsl:template> > > <!--######## Template for Department Main table data > ######--> > <xsl:template match="List"> > <table border="1" width="100%"> > <xsl:apply-templates select="Department"/> > </table> > </xsl:template> > > <!--### Displays first page departments only ###--> > <xsl:template match="Department"> > <xsl:for-each select="/List/Entry/Department[not(. > = preceding::Department)]"> > <tr> > <td> > <span style="color:#000000"> > <a href=""><xsl:value-of select="." /></a> > </span> > </td> > </tr> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> > > An earlier posted fix in the xlst allowed me to > display just single unique entries in the html like > this: > > Accounting and Finance > Maths > Economic History > > However I now get multiples of these unique values > rather than one single list of the unique values. > > Am I calling the template root incorrectly in the > xslt? > Should I be using a loop of some sort to display the > unique values only once? > > Many thanks, > > > Mike > > Yahoo! Mail Stay connected, organized, and protected. Take the tour: http://tour.mail.yahoo.com/mailtour.html
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