Subject: Re: [xsl] transforming XML to XML with XSLT 1.0 From: "Mark Kersten" <markker83@xxxxxxxxxxx> Date: Fri, 20 May 2005 16:16:14 +0200 |
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] transforming XML to XML with XSLT 1.0 Date: Fri, 20 May 2005 15:08:10 +0100
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/>
<xsl:key name="sm" match="Row" use="@SHORT_MESSAGE"/>
<xsl:template match="oda">
<oda>
<aid><xsl:value-of select="Row[1]/@AID"/></aid>
<group>
<type><xsl:value-of select="Row[1]/@GROUP_TYPE"/></type>
<version><xsl:value-of select="Row[1]/@GROUP_VERSION"/></version>
</group>
<timeout><xsl:value-of select="Row[1]/@TIMEOUT"/></timeout>
<xsl:for-each select="Row[generate-id()=generate-id(key('sm',@SHORT_MESSAGE))]">
<shortmessage><xsl:value-of select="@SHORT_MESSAGE"/></shortmessage>
</xsl:for-each>
<odaaccessrights>
<xsl:for-each select="Row">
<number><xsl:value-of select="position()"/></number>
<enabled><xsl:value-of select="@ACCESS_RIGHT"/></enabled>
</xsl:for-each>
</odaaccessrights>
</oda>
</xsl:template>
</xsl:stylesheet>
$ saxon oda.xml oda.xsl <?xml version="1.0" encoding="utf-8"?> <oda> <aid>CD46</aid> <group> <type>08</type> <version>A</version> </group> <timeout>2</timeout> <shortmessage>0066</shortmessage> <shortmessage>6280</shortmessage> <odaaccessrights> <number>1</number> <enabled>0</enabled> <number>2</number> <enabled>0</enabled> <number>3</number> <enabled>1</enabled> </odaaccessrights> </oda>
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