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Subject: RE: [xsl] problems with xsl:copy instruction From: "Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx> Date: Thu, 26 May 2005 15:55:28 +0100 |
> My understanding of how the <xsl:copy> and <xsl:copy-of> commands is
> weak and so am having trouble figuring out the exact problem.
xsl:copy will copy the current element only, without it's attributes or
children, to the result tree.
xsl:copy-of copies everything, attributes and children.
In your root matching template you create a literal result element
<TopConcept>, and then apply-templates on the <TopConcept> element under
the root. The first instruction in the matching template that gets
applied is xsl:copy, so you will get another <TopConcept> in your
output.
The rest of the stylesheet also needs looking at, eg:
<xsl:for-each select="/*/*/O/Class[text()=$notPresent]">
<xsl:apply-templates select="/*/*/O/Class[text()=$notPresent]"/>
</xsl:for-each>
and:
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="@*"/>
</xsl:copy>
</xsl:template>
...are both a bit off but I'm guessing you are trying things out?
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