Subject: RE: [xsl] problems with xsl:copy instruction From: "Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx> Date: Thu, 26 May 2005 15:55:28 +0100 |
> My understanding of how the <xsl:copy> and <xsl:copy-of> commands is > weak and so am having trouble figuring out the exact problem. xsl:copy will copy the current element only, without it's attributes or children, to the result tree. xsl:copy-of copies everything, attributes and children. In your root matching template you create a literal result element <TopConcept>, and then apply-templates on the <TopConcept> element under the root. The first instruction in the matching template that gets applied is xsl:copy, so you will get another <TopConcept> in your output. The rest of the stylesheet also needs looking at, eg: <xsl:for-each select="/*/*/O/Class[text()=$notPresent]"> <xsl:apply-templates select="/*/*/O/Class[text()=$notPresent]"/> </xsl:for-each> and: <xsl:template match="@* | node()"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates select="@*"/> </xsl:copy> </xsl:template> ...are both a bit off but I'm guessing you are trying things out?
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