[xsl] Identify last node in nested nodeset with same name

[Mat Bergman <matbergman@xxxxxxxxx>]

I am working with XML data that shares the same
element name for each node set, for example:

<menu name="link1"/>
<menu name="link2">
     <menu name="link2a"/>
     <menu name="link2b"/>
</menu>

My XSL stylesheet transforms this into an HTML
unordered list, like this:
<ul>
<li>link1</li>
<li>link2
     <ul>
     <li>link2a</li>
     <li>link2b</li>
     </ul>
</li>
</ul>

I can't figure out how to identify the last
second-tier node (in this example "link2b") so that
the stylesheet can write the closing </ul> tag for the
nested list. I thought I would reference it with
something like <xsl:if test="/menu/menu[last()]">, but
my XPath must be incorrect because it fails.

I am currently writing the opening <ul> and closing
</li> tags for the nested list with this:

<xsl:template match="menu">
<xsl:if test="count(menu)>0">
<xsl:text>&lt;ul&gt;</xsl:text>
</xsl:if>

<xsl:if test="count(menu)=0">
<xsl:text>&lt;/li&gt;</xsl:text>
</xsl:if>
</xsl:template>

If I only knew how to identify the last node in
/menu/menu, I could easily write the closing tag.

Thanks,

-Mat




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