Re: [xsl] Displaying one node at a time

Hi,

Tempore 20:02:06, die 07/04/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Fadi Qutaishat <fadi_taher2000@xxxxxxxxx>:

How can I display one chunk at a time, for example,
using a next link.

But word 'link' in this context seems to imply html.

Just a wild guess, but I think your looking for a stylesheet that generates DHTML to dynamically browse your page's chunks:

<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"> <xsl:output method="html" indent="yes" encoding="UTF-8" omit-xml-declaration="yes"/>

<xsl:template match="/">
	<html>
		<head>title
		<script type="text/javascript">
		function show(id) {
		var block=document.getElementsByTagName('div');
		for (i=0;i &lt; block.length;i++) {
			block[i].style.display='none';
		}
		document.getElementById(id).style.display='block';
		}
		</script>
		</head>
		<body onload="show('{//chunk/@id[1]}')">
			<xsl:apply-templates/>
		</body>
	</html>
</xsl:template>

<xsl:template match="page"> <h1>My page</h1> <ul> <xsl:for-each select="chunk"> <li><a href="javascript: show('{@id}')">chunk <xsl:value-of select="@id"/></a></li> </xsl:for-each> </ul> <xsl:apply-templates/> </xsl:template>

<xsl:template match="chunk"> <div id="{@id}" style="display: none"> <h2>chunk <xsl:value-of select="@id"/></h2> <p><xsl:apply-templates/></p> <xsl:if test="position()!=1"> <a href="javascript: show('{preceding-sibling::chunk[1]/@id}')"><<previous chunk |</a> </xsl:if> <xsl:if test="position()!=last()"> <a href="javascript: show('{following-sibling::chunk[1]/@id}')">| next chunk>></a> </xsl:if> </div> </xsl:template>

</xsl:stylesheet>

regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
Spread the wiki (http://www.wikipedia.org)

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