RE: [xsl] Generating Sequential IDs

["Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx>]

> I want to generate the sequence ids for all the nodes in the
> xml tree. For example my source xml looks like this..
> 	<A>
> 		<B></B>
> 		<C>
> 			<D></D>
> 		</C>
> 		<E>
> 			<F>
> 				<G></G>
> 			</F>
> 		</E>
> 	</A>
>
> I want the output xml like..
>
> 	<A id=1>
> 		<B id=2></B>
> 		<C id=3>
> 			<D id=4></D>
> 		</C>
> 		<E id=5>
> 			<F id=6>
> 				<G id=8></G>
> 			</F>
> 		</E>
> 	</A>
>
> Can any one give me the xslt code for this..

<xsl:template match="*">
	<xsl:copy>
		<xsl:copy-of select="@*"/>
		<xsl:attribute name="id">
			<xsl:number level="any" count="*"/>
		</xsl:attribute>
		<xsl:apply-templates select="*"/>
	</xsl:copy>
</xsl:template>

...but if you are using Java I would recommend doing this using an
XMLFilter instead of XSLT.

cheers
andrew