Subject: Re: [xsl] only display if subnodes occur more than once From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 5 Jul 2005 22:46:03 +0100 |
If the input is modified so that sub_b has two groups of repeated elements then the code I just posted repeats the containing element for each group. $ saxon submode.xml submode.xsl <?xml version="1.0" encoding="utf-8"?> <root> <sub_b> <elem_2/> <elem_2/> <elem_2/> </sub_b> <sub_b> <elem_3/> <elem_3/> </sub_b> </root> It may be that you'd prefer these to be re-merged: $ saxon submode.xml submode.xsl <?xml version="1.0" encoding="utf-8"?> <root> <sub_b> <elem_2/> <elem_2/> <elem_2/> <elem_3/> <elem_3/> </sub_b> </root> in which case the stylesheet is a copule of lines longer: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output indent="yes"/> <xsl:key name="x" match="root/*/*" use="concat(generate-id(..),':',name())"/> <xsl:template match="root"> <root> <xsl:for-each select="*"> <xsl:variable name="d" select="*[generate-id()=generate-id(key('x',concat(generate-id(..),':',name()))[2])]"/> <xsl:if test="$d"> <xsl:copy> <xsl:for-each select="$d"> <xsl:copy-of select="key('x',concat(generate-id(..),':',name()))"/> </xsl:for-each> </xsl:copy> </xsl:if> </xsl:for-each> </root> </xsl:template> </xsl:stylesheet> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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