Re: [xsl] Reading two xmls and changing the attribute names in the first xml conditionally

["Joris Gillis" <roac@xxxxxxxxxx>]

Hi,

Tempore 10:34:27, die 07/06/2005 AD, hinc in  
xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Lakshmi narayana  
<lchintala@xxxxxxxxxxxx>:

> 6) Can any one send me the xsl code for this scenario.
consider that the scond file is named 'second.xml' and the stylesheet is  
processed on the first file.

<xsl:stylesheet version="1.0"  
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:output indent="yes" method="xml"/>

<xsl:key name="newName" match="destination"  
use="concat(local-name(../..),../source/@name)"/>

<xsl:template match="node()">
	<xsl:copy>
		<xsl:apply-templates select="@*">
			<xsl:with-param name="Type" select="@Type"/>
		</xsl:apply-templates>
		<xsl:apply-templates select="node()"/>
	</xsl:copy>
</xsl:template>
	
<xsl:template match="@*">
<xsl:param name="Type"/>
<xsl:variable name="name" select="local-name()"/>
<xsl:variable name="newname">
	<xsl:for-each select="document('second.xml')">
		<xsl:value-of select="key('newName',concat($Type,$name))/@name"/>
	</xsl:for-each>
</xsl:variable>
<xsl:attribute name="{$newname}"><xsl:value-of select="."/></xsl:attribute>
</xsl:template>

<xsl:template match="@Type"><xsl:copy/></xsl:template>

</xsl:stylesheet>


will produce:

<A1 A-Element-Name="A1" A-sequence="1" A-Description="optional"  
Type="AGroup">
	<B1 B-Element-Name="B1" B-sequence="101" B-order="first" Type="BGroup"/>
	<B2>
		<C1 C-Element-Name="C1" C-sequence="201" C-order="Sec" Type="CGroup"/>
		<C2 C-Element-Name="C2" C-sequence="202" C-order="Sec" Type="CGroup">
			<C3/>
			<D1 D-Element-Name="D1" D-Min="1" D-Max="1" D-Reference="Trr"  
D-Predicate="" Type="DGroup">
				<C2 C-Element-Name="C2" C-sequence="202" C-order="Sec" Type="CGroup"/>
			</D1>
		</C2>
	</B2>
</A1>


regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
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