[xsl] Copy path specified by parameter

["Steve Lloyd" <steve.lloyd@xxxxxxx>]

I'd like to return a sub-path which is selected by a parameter to the XSLT.
Something like:-

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
version="2.0">
   <xsl:param name="path" select="'/part[1]'"/>  <!-- default value -->

<xsl:template match="$path">
    <xsl:apply-templates  mode="copy"/>
</xsl:template>
  
   <xsl:template match="@*|node()" mode="copy">
       <xsl:copy>
           <xsl:copy-of select="@*"/>
           <xsl:apply-templates mode="copy"/>
       </xsl:copy>
   </xsl:template>
  
</xsl:stylesheet>

What is the best way of going about this? Thanks.

--
Steve Lloyd
XML Developer, Publications  group, International Baccalaureate Organization
Email: steve.lloyd[at]ibo.org
Tel:   +44 (29) 2054 7869
WWW:   http://www.ibo.org