Subject: [xsl] Sum of identical nodes From: Alvin Ng <ngkwangming@xxxxxxxxx> Date: Wed, 20 Jul 2005 14:18:34 +0800 |
Hi, Sorry for this repost... but I needed some help with this. Any help is greatly appreciated. Below is an example of what I hope to acheive In this example, my input files are File1 and File2 and wish to output my result to File3 - add 1 from File1/AAA to 2 from File2/AAA to output File3 - add 2 from File1/AAA to 3 from File2/AAA to output File3 - add 2 from File1/BBB to 0 from File2/BBB to output File3 - add 3 from File1/BBB to 0 from File2/BBB to output File3 Each file in File1 and File2 have few hundreds nodes of <moid></moid> and <mt></mt>. My biggest hindrance is how to recursively sum up each node from each nodeset. File 1: <xml> <moid> AAA </moid> <mt> 1 </mt> <mt> 2 </mt> <moid> BBB </moid> <mt> 2 </mt> <mt> 3 </mt> </xml> File 2: <xml> <moid> AAA </moid> <mt> 2 </mt> <mt> 3 </mt> <moid> BBB </moid> <mt> 0 </mt> <mt> 0 </mt> </xml> File 3: <xml> <moid> AAA </moid> <mt> 3 </mt> <mt> 5 </mt> <moid> BBB </moid> <mt> 2 </mt> <mt> 3 </mt> </xml>
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