Re: [xsl] Applying templates by selecting it

Subject: Re: [xsl] Applying templates by selecting it
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Wed, 20 Jul 2005 10:53:55 -0400
Sylvain,

Also, that template matching "node" isn't doing anything. Try removing it. You'll get the same result.

This is because you have no element named "node", so this template is never matched.

You might have been trying to match "node()", but as you've discovered, this is unnecessary (and in fact will often interfere with what you want).

Cheers,
Wendell

At 10:18 AM 7/20/2005, you wrote:
Ok I found it, it should be

<xsl:apply-templates select="root/a"/>

/me feels sad for wasting so much time...

- sylvain

Selon Sylvain Hellegouarch <sh@xxxxxxxxxx>:

> Hi everyone,
>
> I have the following simple stylesheet :
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> version="1.0">
> <xsl:template match="/">
> <xsl:apply-templates />
> </xsl:template>
>
> <xsl:template match="node">
> <xsl:value-of select="."/>
> </xsl:template>
> </xsl:stylesheet>
>
> Now I have also the following XML document :
>
> <?xml version="1.0" encoding="UTF-8"?>
> <root>
> <a>hello there</a>
> </root>
>
> Everythong works fine and I do get :
>
> <?xml version="1.0" encoding="utf-8"?>
> hello there
>
> But if I change :
>
> <xsl:apply-templates />
>
> To :
>
> <xsl:apply-templates select="a"/>
>
> Then I don't get any output like if it didn't go into the 'a' template.
>
> I'm sure I'm missing something really stupid here but can't see it (shame on
> me).


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
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