Re: [xsl] find position of first occurrence in a node set

[James Neff <jneff@xxxxxxxxxxxxxxxx>]

Yes I did change jobs :)

Thanks for the quick response.

--Jim



JBryant@xxxxxxxxx wrote:

> Hi, James,
>
> Did you change companies? I recall your e-mail used to be something else 
> (or perhaps I mis-remember).
>
> Anyway, you can use the xsl:number instruction to get what you want:
>
> <?xml version="1.0" encoding="UTF-8"?>
>
> <xsl:stylesheet version="2.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
>  <xsl:template match="/">
>    <xsl:number select="transaction_set/segment[@type='HL']"/>
>  </xsl:template>
>
> </xsl:stylesheet>
>
> Just tested it with Saxon 8.4 and got 3.
>
> Jay Bryant
> Bryant Communication Services
> (presently consulting at Synergistic Solution Technologies)
>
>
>
>
> James Neff <jneff@xxxxxxxxxxxxxxxx> 
> 07/29/2005 01:08 PM
> Please respond to
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>
>
> To
> XSL list <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> cc
>
> Subject
> [xsl] find position of first occurrence in a node set
>
>
>
>
>
>
> Greetings,
>
> I have a node set that looks like this:
>
> <transaction_set>
>
>  <segment type='SL'>
>    A
>  </segment>
>
>  <segment type='GS'>
>    B
>  </segment>
>
>  <segment type='HL'>
>    C
>  </segment>
>
>  <segment type='PR'>
>    D
>  </segment>
>
>  ....
>
> </transaction_set>
>
>
> I need to find the position of the first <segment> element that has the 
> type of 'HL'.  So for my example above it should return 3.
>
>
> Thanks you in advance,